(3|4)+lisp files for puzzles 3 and 4
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67
puzzle-3.lisp
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67
puzzle-3.lisp
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(defvar input (uiop:read-file-string "puzzle-3-input.txt"))
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(defun split-string-in-two (s)
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(let ((len (length s)))
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(list (subseq s 0 (/ len 2)) (subseq s (/ len 2)))))
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(defvar inputs (with-input-from-string (s input)
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(loop
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for line = (read-line s nil)
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until (null line)
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collect (split-string-in-two line))))
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(defun string-to-clist (str)
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(loop for char across str collect char))
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(defun common-types (s1 s2)
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(car (intersection
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(string-to-clist s1)
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(string-to-clist s2))))
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(defvar shared (mapcar (lambda (x)
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(destructuring-bind (s1 s2) x
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(common-types s1 s2)))
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inputs))
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(defun priority-map (c)
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(if (upper-case-p c)
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(+ 27 (- (char-code c) (char-code #\A)))
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(+ 1 (- (char-code c) (char-code #\a)))))
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(defvar round-1-answer (reduce #'+ (mapcar #'priority-map shared)))
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;; Round 2
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;; Simple recursive algorithm which produces consecutive groups of 3 elements
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(defun group-by-3 (lst)
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(if (null lst)
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nil
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(cons
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(list (car lst) (car (cdr lst)) (car (cdr (cdr lst))))
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(group-by-3 (cdr (cdr (cdr lst)))))))
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;; Note the use of group-by-3 here
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(defvar inputs (group-by-3
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(with-input-from-string (s input)
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(loop
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for line = (read-line s nil)
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until (null line)
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collect line))))
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;; Extend intersection to three
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(defun common-types-3 (s1 s2 s3)
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(car
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(intersection
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(string-to-clist s1)
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(intersection
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(string-to-clist s2)
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(string-to-clist s3)))))
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;; Extend the destructuring bind and use of common-types-3
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(defvar shared (mapcar (lambda (x)
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(destructuring-bind (s1 s2 s3) x
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(common-types-3 s1 s2 s3)))
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inputs))
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;; Same as before
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(defvar round-2-answer (reduce #'+ (mapcar #'priority-map shared)))
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59
puzzle-4.lisp
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59
puzzle-4.lisp
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;; Example input: a-b,c-d which denotes [a,b] and [c,d]
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;; We want to find if [c,d] < [a,b] or vice versa (complete inclusion)
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;; and since we're working with integers, it's simply checking if the
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;; bounds are included i.e. c in [a,b] and d in [a,b]
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(defvar input (uiop:read-file-string "puzzle-4-input.txt"))
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(defun parse-bound (str)
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"Given STR=\"a-b\" return (a b)"
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(let* ((sep (search "-" str))
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(first (subseq str 0 sep))
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(second (subseq str (+ sep 1))))
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(list (parse-integer first) (parse-integer second))))
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(defvar completed-parse
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(with-input-from-string (s input)
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(loop for line = (read-line s nil)
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until (null line)
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collect
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;; given a-b,c-d we want ((a b) (c d))
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(let* ((sep (search "," line))
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(first-bound (subseq line 0 sep))
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(second-bound (subseq line (+ sep 1))))
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(list (parse-bound first-bound) (parse-bound second-bound))))))
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(defun complete-inclusion (first-bound second-bound)
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(destructuring-bind (a b) first-bound
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(destructuring-bind (c d) second-bound
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(or
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(and
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(>= a c) (<= a d)
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(>= b c) (<= b d))
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(and
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(>= c a) (<= c b)
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(>= d a) (<= d b))))))
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(defvar round-1-answer (length (remove-if #'null
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(mapcar (lambda (pair)
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(destructuring-bind (first second) pair
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(complete-inclusion first second)))
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completed-parse))))
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;; Round 2: any overlap at all. Basically just overhaul the inclusion
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;; function and then do the same answer checking.
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(defun any-inclusion (first second)
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(destructuring-bind (a b) first
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(destructuring-bind (c d) second
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;; How about doing this through negation? [a,b] does not overlap with [c,d] at all if either b < c or a > d.
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(not
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(or
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(< b c)
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(> a d))))))
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(defvar round-2-answer (length (remove-if #'null
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(mapcar (lambda (pair)
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(destructuring-bind (first second) pair
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(any-inclusion first second)))
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completed-parse))))
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