(powerset)~Common Lisp -> Racket
Decided to try my hand at racket, fundamentally the algorithm is the same and code structure is basically the same anyway. Just looks cleaner.
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;;; powerset.lisp --- A program to find the power set of some set
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;; Copyright (C) 2021 Aryadev Chavali
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;; Author: Aryadev Chavali <aryadev@aryadevchavali.com>
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;; This program is free software; you can redistribute it and/or modify
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;; it under the terms of the GNU General Public License as published by
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;; the Free Software Foundation, either version 3 of the License, or
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;; (at your option) any later version.
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;; This program is distributed in the hope that it will be useful,
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;; but WITHOUT ANY WARRANTY; without even the implied warranty of
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;; MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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;; GNU General Public License for more details.
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;; You should have received a copy of the GNU General Public License
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;; along with this program. If not, see <https://www.gnu.org/licenses/>.
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;;; Commentary:
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;; This program provides a naive counting based approach to finding
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;; specifically sized subsets of some set then using that to generate
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;; the power set. We start by looking for subsets of size n.
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;;; Code:
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24
powerset.rkt
Normal file
24
powerset.rkt
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#lang racket
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(define (subsets-of lst n)
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(cond
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[(null? lst) null] ; 0 ways of making anything out of empty set
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[(= n 0) (list null)] ; 1 way of making a 0 sized subset of something
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[(= n 1) (map list lst)] ; |lst| ways of making singletons
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[else
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(let ([head (car lst)]
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[tail (cdr lst)])
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(append
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;; HEAD is a part of the subset, so the rest of the subset
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;; must be an n-1 sized subset of TAIL
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(map (lambda (lst) (cons head lst))
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(subsets-of tail (- n 1)))
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;; ... or HEAD is not part of the subset, so the subset is
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;; some n sized subset of TAIL
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(subsets-of tail n)))]))
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(define (powerset lst)
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(append* ; flatten list of n sized subsets to just get subsets
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(map (lambda (n)
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(subsets-of lst n)) ; get subset of size n
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(range 0 (+ 1 (length lst)))))) ; n from 0 to |lst|
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