From 33898c4eea337128e26fc5c7eaf245b12c8bd452 Mon Sep 17 00:00:00 2001 From: Aryadev Chavali Date: Mon, 26 Jun 2023 08:35:43 +0100 Subject: (*->2022)~made it clear what advent of code I'm doing --- 2022/puzzle-4.lisp | 59 ++++++++++++++++++++++++++++++++++++++++++++++++++++++ 1 file changed, 59 insertions(+) create mode 100644 2022/puzzle-4.lisp (limited to '2022/puzzle-4.lisp') diff --git a/2022/puzzle-4.lisp b/2022/puzzle-4.lisp new file mode 100644 index 0000000..04c7bfb --- /dev/null +++ b/2022/puzzle-4.lisp @@ -0,0 +1,59 @@ +;; Example input: a-b,c-d which denotes [a,b] and [c,d] + +;; We want to find if [c,d] < [a,b] or vice versa (complete inclusion) +;; and since we're working with integers, it's simply checking if the +;; bounds are included i.e. c in [a,b] and d in [a,b] + +(defvar input (uiop:read-file-string "2022/4-input")) + +(defun parse-bound (str) + "Given STR=\"a-b\" return (a b)" + (let* ((sep (search "-" str)) + (first (subseq str 0 sep)) + (second (subseq str (+ sep 1)))) + (list (parse-integer first) (parse-integer second)))) + +(defvar completed-parse + (with-input-from-string (s input) + (loop for line = (read-line s nil) + until (null line) + collect + ;; given a-b,c-d we want ((a b) (c d)) + (let* ((sep (search "," line)) + (first-bound (subseq line 0 sep)) + (second-bound (subseq line (+ sep 1)))) + (list (parse-bound first-bound) (parse-bound second-bound)))))) + +(defun complete-inclusion (first-bound second-bound) + (destructuring-bind (a b) first-bound + (destructuring-bind (c d) second-bound + (or + (and + (>= a c) (<= a d) + (>= b c) (<= b d)) + (and + (>= c a) (<= c b) + (>= d a) (<= d b)))))) + +(defvar round-1-answer (length (remove-if #'null + (mapcar (lambda (pair) + (destructuring-bind (first second) pair + (complete-inclusion first second))) + completed-parse)))) + +;; Round 2: any overlap at all. Basically just overhaul the inclusion +;; function and then do the same answer checking. +(defun any-inclusion (first second) + (destructuring-bind (a b) first + (destructuring-bind (c d) second + ;; How about doing this through negation? [a,b] does not overlap with [c,d] at all if either b < c or a > d. + (not + (or + (< b c) + (> a d)))))) + +(defvar round-2-answer (length (remove-if #'null + (mapcar (lambda (pair) + (destructuring-bind (first second) pair + (any-inclusion first second))) + completed-parse)))) -- cgit v1.2.3-13-gbd6f