1 files changed, 0 insertions, 59 deletions
diff --git a/puzzle-4.lisp b/puzzle-4.lisp
deleted file mode 100644
index be842d3..0000000
--- a/puzzle-4.lisp
+++ /dev/null
@@ -1,59 +0,0 @@
-;; Example input: a-b,c-d which denotes [a,b] and [c,d]
-
-;; We want to find if [c,d] < [a,b] or vice versa (complete inclusion)
-;; and since we're working with integers, it's simply checking if the
-;; bounds are included i.e. c in [a,b] and d in [a,b]
-
-(defvar input (uiop:read-file-string "puzzle-4-input.txt"))
-
-(defun parse-bound (str)
-  "Given STR=\"a-b\" return (a b)"
-  (let* ((sep (search "-" str))
-         (first (subseq str 0 sep))
-         (second (subseq str (+ sep 1))))
-    (list (parse-integer first) (parse-integer second))))
-
-(defvar completed-parse
-  (with-input-from-string (s input)
-    (loop for line = (read-line s nil)
-          until (null line)
-          collect
-          ;; given a-b,c-d we want ((a b) (c d))
-          (let* ((sep (search "," line))
-                 (first-bound (subseq line 0 sep))
-                 (second-bound (subseq line (+ sep 1))))
-            (list (parse-bound first-bound) (parse-bound second-bound))))))
-
-(defun complete-inclusion (first-bound second-bound)
-  (destructuring-bind (a b) first-bound
-    (destructuring-bind (c d) second-bound
-      (or
-       (and
-        (>= a c) (<= a d)
-        (>= b c) (<= b d))
-       (and
-        (>= c a) (<= c b)
-        (>= d a) (<= d b))))))
-
-(defvar round-1-answer (length (remove-if #'null
-                                          (mapcar (lambda (pair)
-                                               (destructuring-bind (first second) pair
-                                                 (complete-inclusion first second)))
-                                             completed-parse))))
-
-;; Round 2: any overlap at all.  Basically just overhaul the inclusion
-;; function and then do the same answer checking.
-(defun any-inclusion (first second)
-  (destructuring-bind (a b) first
-    (destructuring-bind (c d) second
-      ;; How about doing this through negation?  [a,b] does not overlap with [c,d] at all if either b < c or a > d.
-      (not
-       (or
-        (< b c)
-        (> a d))))))
-
-(defvar round-2-answer (length (remove-if #'null
-                                          (mapcar (lambda (pair)
-                                               (destructuring-bind (first second) pair
-                                                 (any-inclusion first second)))
-                                             completed-parse))))